(2x^3y^2/-x^2y^5)^-2

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Solution for (2x^3y^2/-x^2y^5)^-2 equation: 


D( x )

(-x)^2 = 0

((2*x^3*y^2)/((-x)^2))*y^5 = 0

(-x)^2 = 0

(-x)^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

((2*x^3*y^2)/((-x)^2))*y^5 = 0

((2*x^3*y^2)/((-x)^2))*y^5 = 0

2*x*y^7 = 0 // : 2*y^7

x = 0

x in (-oo:0) U (0:+oo)

(((2*x^3*y^2)/((-x)^2))*y^5)^-2 = 0

1/4*x^-2*y^-14 = 0 // : 1/4*y^-14

x^-2 = 0

x naleu017Cy do O

x belongs to the empty set

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